SATHEE: Structure of Atom - Result Question 4

Structure of Atom - Result Question 4

####4. The energies $E_{1}$ and $E_{2}$ of two radiations are 25 $e V$ and $50 e V$ , respectively. The relation between their wavelengths i.e., $λ_{1}$ and $λ_{2}$ will be: [2011]

(a) $λ_{1} = λ_{2}$

(b) $λ_{1} = 2 λ_{2}$

(d) $λ_{1} = \frac{1}{2} λ_{2}$

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Solution:

(b) Given $E_{1} = 25 e V E_{2} = 50 e V$

$\begin{aligned} E_{1} = \frac{h c}{λ_{1}} E_{2} = \frac{h c}{λ_{2}} ∴ \frac{E_{1}}{E_{2}} = \frac{λ_{2}}{λ_{1}} \\ ∴ \frac{λ_{2}}{λ_{1}} = \frac{25}{50} = \frac{1}{2} ∴ λ_{1} = 2 λ_{2} \end{aligned}$

Structure of Atom - Result Question 4

Solution:

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Structure of Atom - Result Question 4

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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