SATHEE: Structure of Atom - Result Question 37

Structure of Atom - Result Question 37

####41. The orbital angular momentum of a $p$ -electron is given as :

[2012 M]

(a) $\frac{h}{\sqrt{2} π}$

(b) $\sqrt{3} \frac{h}{2 π}$

(d) $\sqrt{6} \cdot \frac{h}{2 π}$

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Solution:

(a) Orbital angular momentum

$= \frac{h}{2 π} \sqrt{ℓ (ℓ + 1)}$

For $p$ orbital $ℓ = 1$

$So, = \frac{h}{2 π} \sqrt{2} = \frac{h}{\sqrt{2} π}$

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Structure of Atom - Result Question 37

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