Structure of Atom - Result Question 33
####35. Orbital having 3 angular nodes and 3 total nodes is
(a) $6 d$
(b) $5 p$
(c) $3 d$
(d) $4 f$
[NEET Odisha 2019]
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Solution:
- (d) Total number of nodes $=(n-1)$
$ 3=n-1 \quad \Rightarrow \quad n=4 $
Number of angular nodes $=1=3 \Rightarrow f$-subshell
$ \begin{aligned} & \text{ (a) } 5 f \quad 5+3=8 \\ & 6 p \quad 6+1=7 \\ & 5 p \longdiv { 7 } \square 5 + 1 = 6 \\ & 4 d \quad 4+2=6 \\ & 5 f>6 p>5 p>4 d \end{aligned} $
