Structure of Atom - Result Question 25
####27. The measurement of the electron position if associated with an uncertainty in momentum, which is equal to $1 \times 10^{-18} g cm s^{-1}$. The uncertainty in electron velocity is,
[2008] (mass of an electron is $9 \times 10^{-28} g$ )
(a) $1 \times 10^{9} cm s^{-1}$
(b) $1 \times 10^{6} cm s^{-1}$
(c) $1 \times 10^{5} cm s^{-1}$
(d) $1 \times 10^{11} cm s^{-1}$
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Solution:
- (a) $\Delta p=m \Delta v$
Substituting the given values of $\Delta x$ and $m$, we get $1 \times 10^{-18} gcms^{-1}=9 \times 10^{-28} g \times \Delta v$
or $\Delta v=\frac{1 \times 10^{-18}}{9 \times 10^{-28}}$
$=1.1 \times 10^{9} cm s^{-1} \simeq 1 \times 10^{9} cm s^{-1}$
