Structure of Atom - Result Question 21

####21. The energy of an electron in the $n^{\text{th }}$ Bohr orbit of hydrogen atom is

[1992]

(a) $-\frac{13.6}{n^{4}} eV$

(b) $-\frac{13.6}{n^{3}} eV$

(c) $-\frac{13.6}{n^{2}} eV$

(d) $-\frac{13.6}{n} eV$

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Solution:

  1. (c) Energy of an electron in Bohr’s orbit is given by the relationship. $E_n=-\frac{13.6}{n^{2}} eV$.

(a) Radius of $n^{\text{th }}$ orbit $=r_1 n^{2}$. (for $H$-atom)



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