Structure of Atom - Result Question 21
####21. The energy of an electron in the $n^{\text{th }}$ Bohr orbit of hydrogen atom is
[1992]
(a) $-\frac{13.6}{n^{4}} eV$
(b) $-\frac{13.6}{n^{3}} eV$
(c) $-\frac{13.6}{n^{2}} eV$
(d) $-\frac{13.6}{n} eV$
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Solution:
- (c) Energy of an electron in Bohr’s orbit is given by the relationship. $E_n=-\frac{13.6}{n^{2}} eV$.
(a) Radius of $n^{\text{th }}$ orbit $=r_1 n^{2}$. (for $H$-atom)
