Structure of Atom - Result Question 14
####14. The energy of second Bohr orbit of the hydrogen atom is $-328 kJ mol^{-1}$; hence the energy of fourth Bohr orbit would be:
[2005]
(a) $-41 kJ mol^{-1}$
(b) $-82 kJ mol^{-1}$
(c) $-164 kJ mol^{-1}$
(d) $-1312 kJ mol^{-1}$
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Solution:
- (b) $E_n=E_1 \times(\frac{Z}{n})^{2}$
$E_2=\frac{E_1}{2^{2}}=-328 kJ / mol$
$E_4=\frac{E_1}{4^{2}}$
$\Rightarrow \frac{E_4}{E_2}=\frac{2^{2}}{4^{2}}=\frac{1}{2^{2}}$
$\Rightarrow E_4=\frac{E_2}{2_2}=\frac{-328}{4} kJ / mol=-82 kj / mol$
