Structure of Atom - Result Question 12
####12. Based on equation $E=-2.178 \times 10^{-18}(\frac{Z^{2}}{n^{2}}) J$, certain conclusions are written. Which of them is not correct?
[NEET 2013]
(a) Larger the value of $n$, the larger is the orbit radius.
(b) Equation can be used to calculate the change in energy when the electron changes orbit.
(c) For $n=1$, the electron has a more negative energy than it does for $n=6$ which mean that the electron is more loosely bound in the smallest allowed orbit.
(d) The negative sign in equation simply means that the energy or electron bound to the nucleus is lower than it would be if the electrons were at the infinite distance from the nucleus.
Show Answer
Solution:
- (c) The electrons has more negative energy in lower orbits that in higher orbit and also the electrons are more tightly bound in the smallest allowed orbit.
Energy of an electron at infinite distance from the nucleus is zero. As an electron approaches the nucleus, the electron attraction increases and hence the energy of electron decreases and thus becomes negative. Thus as the value of $n$ decreases, i.e. lower the orbit is, more negative is the energy of the electron in it.
