SATHEE: States of Matter - Result Question 9

States of Matter - Result Question 9

####9. A bubble of air is underwater at temperature $15^{\circ} C$ and the pressure $1.5 b a r$ . If the bubble rises to the surface where the temperature is $25^{\circ} C$ and the pressure is $1.0 b a r$ , what will happen to the volume of the bubble?

[2011M]

(a) Volume will become greater by a factor of 1.6.

(b) Volume will become greater by a factor of 1.1.

(d) Volume will become greater by a factor of 2.5.

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Solution:

(a) Given

$P_{1} = 1.5$ bar, $T_{1} = 273 + 15 = 288 K, V_{1} = V$

$P_{2} = 1.0$ bar, $T_{2} = 273 + 25 = 298 K, V_{2} =$ ?

$\frac{P_{1} V_{1}}{T_{1}} = \frac{P_{2} V_{2}}{T_{2}}$

$\frac{1.5 \times V}{288} = \frac{1 \times V_{2}}{298}$

$V_{2} = 1.55 V$ i.e., volume of bubble will be almost 1.6 time to initial volume of bubble.

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States of Matter - Result Question 9

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