SATHEE: States of Matter - Result Question 4

States of Matter - Result Question 4

####4. Equal masses of $H_{2}, O_{2}$ and methane have been taken in a container of volume $V$ at temperature $27^{\circ} C$ in identical conditions. The ratio of the volumes of gases $H_{2} : O_{2}$ : methane would be :

(a) $8 : 16 : 1$

(b) $16 : 8 : 1$ [2014]

(c) $16 : 1 : 2$

(d) $8 : 1 : 2$

Show Answer

Solution:

(c) According to Avogadro’s law “At same temperature and pressure. Volume $\propto$ no. of moles”

$n_{H_{2}} = \frac{w}{2}; n_{O_{2}} = \frac{w}{32}; n_{C H_{4}} = \frac{w}{16}$

$∵ V_{H_{2}} : V_{O_{2}} : V_{C H_{4}} = n_{H_{2}} : n_{O_{2}} : n_{C H_{4}}$

$= \frac{w}{2} : \frac{w}{32} : \frac{w}{16} = 16 : 1 : 2$

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States of Matter - Result Question 4

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