States of Matter - Result Question 2
####2. The volume occupied by $1.8 g$ of water vapour at $374^{\circ} C$ and 1 bar pressure will be
[Use $R=0.083 bar LK^{-1} mol^{-1}$ ]
[NEET Odisha 2019]
(a) $5.37 L$
(b) $96.66 L$
(c) $55.87 L$
(d) $3.10 L$
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Solution:
- (a) According to ideal gas equation.
$PV=nRT$
$V=\frac{W}{M}(\frac{RT}{P})$
$V=\frac{1.8}{18} \times \frac{0.083 \times 647}{1}=5.37 L$
