States of Matter - Result Question 12
####12. A gaseous mixture contains $H_2$ and $O_2$ in the molar ratio $8: 1$. The ratio of $H_2: O_2$ by weight in this mixture would be
[1999]
(a) $4: 1$
(b) $1: 8$
(c) $8: 1$
(d) $1: 2$
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Solution:
- (d) $\frac{\text{ Moles of } H_2}{\text{ Moles of } O_2}=\frac{8}{1}$ (Given) $(\frac{\text{ M.W. of } O_2}{\text{ M.W. of } H_2}) \cdot(\frac{\text{ weight of } H_2}{\text{ weight of } O_2})=\frac{8}{1}$
$\frac{\text{ weight of } H_2}{\text{ weight of } O_2}=\frac{8 \times 2}{32 \times 1}=\frac{1}{2}$
