SATHEE: States of Matter - Result Question 12

States of Matter - Result Question 12

####12. A gaseous mixture contains $H_{2}$ and $O_{2}$ in the molar ratio $8 : 1$ . The ratio of $H_{2} : O_{2}$ by weight in this mixture would be

[1999]

(a) $4 : 1$

(b) $1 : 8$

(c) $8 : 1$

(d) $1 : 2$

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Solution:

(d) $\frac{Moles of H_{2}}{Moles of O_{2}} = \frac{8}{1}$ (Given) $(\frac{M.W. of O_{2}}{M.W. of H_{2}}) \cdot (\frac{weight of H_{2}}{weight of O_{2}}) = \frac{8}{1}$

$\frac{weight of H_{2}}{weight of O_{2}} = \frac{8 \times 2}{32 \times 1} = \frac{1}{2}$

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