Some Basic Concepts of Chemistry - Result Question 53
####53. A 5 molar solution of $H_2 SO_4$ is diluted from 1 litre to a volume of 10 litres, the normality of the solution will be :
[1991]
(a) $1 N$
(b) $0.1 N$
(c) $5 N$
(d) $0.5 N$
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Solution:
54 .
(a) $5 MH_2 SO_4=10 NH_2 SO_4$, $(\because.$ Basicity of $H_2 SO_4=2$ )
$N_1 V_1=N_2 V_2$, $10 \times 1=N_2 \times 10$ or $N_2=1 N$
(a) $Mg^{2+}+Na_2 CO_3 \longrightarrow MgCO_3+2 Na^{+}$
$1 g$ eq. $1 g$ eq.
$1 g$ eq. of $Mg^{2+}=12 g$ of $Mg^{2+}=12000 mg$
$=1000$ milli eq. of $Na_2 CO_3$
$\therefore 12 mg Mg^{2+}=1$ milli eq. $Na_2 CO_3$
