SATHEE: Some Basic Concepts of Chemistry

Some Basic Concepts of Chemistry - Result Question 52

####52. Liquid benzene $(C_{6} H_{6})$ burns in oxygen according to the equation

$2 C_{6} H_{6} (l) + 15 O_{2} (g) ⟶ 12 C O_{2} (g) + 6 H_{2} O (g)$

How many litres of $O_{2}$ at STP are needed to complete the combustion of $39 g$ of liquid benzene? (Mol. wt. of $O_{2} = 32, C_{6} H_{6} = 78$ )

(a) $74 L$

(b) $11.2 L$

(d) $84 L$

[1996]

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Solution:

(d) $2 C_{6} H_{6} + 15 O_{2} (g) ⟶ 12 C O_{2} (g) + 6 H_{2} O (g)$ 2(78) 15(32)

$∵ 156 g$ of benzene, required oxygen $= 15 \times 22.4$ litre

$∴ 1 g$ of benzene, required oxygen $= \frac{15 \times 22.4}{156}$ litre

$∴ 39 g$ of benzene, required oxygen

$= \frac{15 \times 22.4 \times 39}{156} = 84.0 litre$

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Some Basic Concepts of Chemistry - Result Question 52

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