Some Basic Concepts of Chemistry - Result Question 47

####47. How many moles of lead (II) chloride will be formed from a reaction between 6.5g of PbO and 3.2g of HCl ?

(a) 0.044

(b) 0.333

(c) 0.011

(d) 0.029

[2008]

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Solution:

  1. (d) Writing the equation for the reaction, we get

PbO+2HClPbCl2+H2O207+162×36.5207+71=223g=73g=278g

From this equation we find 223g of PbO reacts with 73g of HCl to form 278g of PbCl2.

If we carry out the reaction between 3.2gHCl and 6.5gPbO.

Amount of PbO that reacts with 3.2gHCl =22373×3.2=9.77g.

Since amount of PbO present is only 6.5g so PbO is the limiting reagent.

Amount of PbCl2 formed by 6.5g of PbO

=278223×6.5g

Number of moles of PbCl2 formed

=278223×6.5278 moles =0.029 moles.



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