SATHEE: Some Basic Concepts of Chemistry

Some Basic Concepts of Chemistry - Result Question 45

####45. What is the $[O \overset{―}{H}]$ in the final solution prepared by mixing $20.0 m L$ of $0.050 M H C l$ with $30.0 m L$ of $0.10 M B a (O H)_{2}$ ?

[2009]

(a) $0.40 M$

(b) $0.0050 M$

(d) $0.10 M$

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Solution:

(d) No. of milli equivalent of $H C l$

$= 20 \times 0.05 = 1.0$

No. of milli equivalent of $B a (O H)_{2}$

$= 30 \times 0.1 \times 2 = 6.0$

After neutralization, no. of milli equivalents in $50 m L$ . of solution $= (6 - 1) = 5$

Total volume of the solution $= 20 + 30 = 50 m L$

$∴$ No. of equivalent of $O H^{-}$ in $50 m L$ is

$[O H^{-}] = \frac{5 \times 1000}{50} \times 10^{- 3} = 0.1 M$

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Some Basic Concepts of Chemistry - Result Question 45

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