Some Basic Concepts of Chemistry - Result Question 45
####45. What is the $[O \overline{H}]$ in the final solution prepared by mixing $20.0 mL$ of $0.050 MHCl$ with $30.0 mL$ of $0.10 MBa(OH)_2$ ?
[2009]
(a) $0.40 M$
(b) $0.0050 M$
(c) $0.12 M$
(d) $0.10 M$
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Solution:
- (d) No. of milli equivalent of $HCl$
$=20 \times 0.05=1.0$
No. of milli equivalent of $Ba(OH)_2$
$=30 \times 0.1 \times 2=6.0$
After neutralization, no. of milli equivalents in $50 mL$. of solution $=(6-1)=5$
Total volume of the solution $=20+30=50 mL$
$\therefore$ No. of equivalent of $OH^{-}$in $50 mL$ is
$[OH^{-}]=\frac{5 \times 1000}{50} \times 10^{-3}=0.1 M$
