SATHEE: Some Basic Concepts of Chemistry - Result Question 44

Some Basic Concepts of Chemistry - Result Question 44

####44. $6.02 \times 10^{20}$ molecules of urea are present in $100 m L$ of its solution. The concentration of solution is :

(a) $0.01 M$

(b) $0.001 M$

(c) $0.1 M$

(d) $0.02 M$

[NEET 2013]

Show Answer

Solution:

(a) $M = \frac{6.02 \times 10^{20} \times 1000}{100 \times 6.02 \times 10^{23}} = \frac{6.02 \times 10^{21}}{6.02 \times 10^{23}}$

$= 0.01 M$

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