Some Basic Concepts of Chemistry - Result Question 44
####44. $6.02 \times 10^{20}$ molecules of urea are present in $100 mL$ of its solution. The concentration of solution is :
(a) $0.01 M$
(b) $0.001 M$
(c) $0.1 M$
(d) $0.02 M$
[NEET 2013]
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Solution:
- (a) $M=\frac{6.02 \times 10^{20} \times 1000}{100 \times 6.02 \times 10^{23}}=\frac{6.02 \times 10^{21}}{6.02 \times 10^{23}}$
$=0.01 M$
