Some Basic Concepts of Chemistry - Result Question 43
####43. In an experiment it showed that $10 mL$ of $0.05 M$ solution of chloride required $10 mL$ of $0.1 M$ solution of $AgNO_3$, which of the following will be the formula of the chloride ( $X$ stands for the symbol of the element other than chlorine):
(a) $X_2 Cl$
(b) $X_2 Cl_2$
(c) $X Cl_2$
(d) $XCl_4$
[NEET Kar. 2013]
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Solution:
- (c) Millimoles of solution of chloride
$ =0.05 \times 10=0.5 $
Millimoles of $AgNO_3$ solution $=10 \times 0.1=1$
So, the millimoles of $AgNO_3$ are double than the chloride solution.
$\therefore X Cl_2+2 AgNO_3 \longrightarrow 2 AgCl+X(NO_3)_2$
