Some Basic Concepts of Chemistry - Result Question 4

####7. When 22.4 litres of H2(g) is mixed with 11.2 litres of Cl2(g), each at S.T.P., the moles of HCl(g) formed is equal to :

[2014]

(a) 1 mole of HCl(g)

(b) 2 moles of HCl(g)

(c) 0.5 moles of HCl(g)

(d) 1.5 moles of HCl (g)

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Solution:

  1. (a) H2 (g) +Cl2 (g) 2HCl(g)

(4) Moles of water =0.0022422.4=104

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