Some Basic Concepts of Chemistry - Result Question 38

####38. The percentage weight of Zn in white vitriol [ZnSO47H2O] is approximately equal to ( Zn=65,S=32,O=16 and H=1 )

(a) 33.65

(b) 32.56

(c) 23.65

(d) 22.65

[1995]

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Solution:

  1. (d) Molecular weight of ZnSO47H2O =65+32+(4×16)+7(2×1+16)=287.

percentage mass of zinc (Zn)

=65287×100=22.65



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