Some Basic Concepts of Chemistry - Result Question 37
####37. An organic compound containing $C, H$ and $N$ gave the following analysis :
$C=40 % ; H=13.33 % ; N=46.67 %$
Its empirical formula would be
[1998]
(a) $C_2 H_7 N_2$
(c) $CH_4 N$
(b) $CH_5 N$
(d) $C_2 H_7 N$
Show Answer
Solution:
- (c) As the sum of the percentage of $C, H & N$ is 100 . Thus, it does not contains $O$ atom.
Table for empirical formula
\begin{tabular}{lllll} \hline Element % & \begin{tabular}{l} At. \\ wt. \end{tabular} & \begin{tabular}{l} Relative \\ Number \end{tabular} & Ratio \\ \hline $C$ & 40.00 & 12 & $\frac{40}{12}=3.33$ & $\frac{3.33}{3.33}=1$ \\ \hline $H$ & 13.33 & 1 & $\frac{13.33}{1}=13.33$ & $\frac{13.33}{3.33}=4$ \\ \hline $N$ & 46.67 & 14 & $\frac{46.67}{14}=3.33$ & $\frac{3.33}{3.33}=1$ \\ \hline \end{tabular}
Hence, empirical formula $=CH_4 N$
