SATHEE: Some Basic Concepts of Chemistry

Some Basic Concepts of Chemistry - Result Question 36

####35. Percentage of Se in peroxidase anhydrase enzyme is $0.5$ by weight (at. wt. $= 78.4$ ) then minimum molecular weight of peroxidase anhydrase enzyme is

(a) $1.568 \times 10^{3}$

(b) 15.68

(d) $1.568 \times 10^{4}$

[2001]

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Solution:

(d) Suppose the mol. wt. of enzyme $= x$

Given $100 g$ of enzyme wt of $S e = 0.5 g$

$∴$ In $x$ g of enzyme wt. of $S e = \frac{0.5}{100} \times x$

Hence $78.4 = \frac{0.5 \times x}{100}$

$∴ x = 15680 = 1.568 \times 10^{4}$ (c) Table for empirical formula :

$Unknown environment 'tabular'$ & $Unknown environment 'tabular'$ & Ratio \ \hline $C$ & 40 & 12 & $\frac{40}{12} = 3.33$ & $\frac{3.33}{3.33} = 1$ \ \hline $H$ & 6.66 & 1 & $\frac{6.66}{1} = 6.66$ & $\frac{6.66}{3.33} = 2$ \ \hline $O$ & 53.34 & 16 & $\frac{53.34}{16} = 3.33$ & $\frac{3.33}{3.33} = 1$ \ \hline \end{tabular}

(% of $O$ in organic compound

$= 100 - (40 + 6.66) = 53.34$

$∴$ Empirical formula of organic compound $= C H_{2} O$ .

Some Basic Concepts of Chemistry - Result Question 36

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Some Basic Concepts of Chemistry - Result Question 36

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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