Some Basic Concepts of Chemistry - Result Question 34
####33. At S.T.P. the density of $CCl_4$ vapours in $g / L$ will be nearest to :
[1988]
(a) 6.87
(b) 3.42
(c) 10.26
(d) 4.57
Topic 2: Percent Composition and Empirical Formula
Show Answer
Solution:
- (a) $1 mol CCl_4$ vapour $=12+4 \times 35.5$
$=154 g \equiv 22.4 L$ at STP
\begin{tabular}{|c|c|c|c|c|} \hline Element & $%$ & \begin{tabular}{l} Atomic \\ weight \end{tabular} & \begin{tabular}{l} Atomic \\ ratio \end{tabular} & $\underset{\text{ ratio }}{\text{ Simple }}$ \\ \hline $C$ & 38.71 & 12 & $\frac{38.71}{12}=3.23$ & $\frac{3.23}{3.23}=1$ \\ \hline $H$ & 9.67 & 1 & $\frac{9.67}{1}=9.67$ & $\frac{9.67}{3.23}=3$ \\ \hline $O$ & \begin{tabular}{c} $100-$ \\ $(38.71+9.67)$ \\ $=51.62$ \end{tabular} & 16 & $\frac{51.62}{16}=3.23$ & $\frac{3.23}{3.23}=1$ \\ \hline \end{tabular}
$\therefore$ Density $=\frac{154}{22.4} gL^{-1}=6.875 gL^{-1}$
