SATHEE: Some Basic Concepts of Chemistry - Result Question 31

Some Basic Concepts of Chemistry - Result Question 31

####29. The number of gram molecules of oxygen in $6.02 \times 10^{24} C O$ molecules is

[1990]

(a) $10 g$ molecules

(b) $5 g$ molecules

(c) $1 g$ molecules

(d) $0.5 g$ molecules

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Solution:

(b) $6.02 \times 10^{23}$ molecules of $C O = 1 m o l e$ of $C O$ $6.02 \times 10^{24} C O$ molecules $= 10$ moles of $C O$ $= 10 g$ atoms of $O = 5 g$ molecules of $O_{2}$

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