Some Basic Concepts of Chemistry - Result Question 31
####29. The number of gram molecules of oxygen in $6.02 \times 10^{24} CO$ molecules is
[1990]
(a) $10 g$ molecules
(b) $5 g$ molecules
(c) $1 g$ molecules
(d) $0.5 g$ molecules
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Solution:
- (b) $6.02 \times 10^{23}$ molecules of $CO=1 mole$ of $CO$ $6.02 \times 10^{24} CO$ molecules $=10$ moles of $CO$ $=10 g$ atoms of $O=5 g$ molecules of $O_2$
