Some Basic Concepts of Chemistry - Result Question 29
####28. The number of oxygen atoms in $4.4 g$ of $CO_2$ is
[1990]
(a) $1.2 \times 10^{23}$
(b) $6 \times 10^{22}$
(c) $6 \times 10^{23}$
(d) $12 \times 10^{23}$
(1900)
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Solution:
- (a) $1 mol$ of $CO_2=44 g$ of $CO_2$
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