SATHEE: Some Basic Concepts of Chemistry

Some Basic Concepts of Chemistry - Result Question 24

####23. The weight of one molecule of a compound $C_{60} H_{122}$ is

[1995]

(a) $1.2 \times 10^{- 20}$ gram

(b) $1.4 \times 10^{- 21}$ gram

(d) $6.023 \times 10^{23}$ gram

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Solution:

(b) Molecular weight of $C_{60} H_{122}$ $= (12 \times 60) + 122 = 842$ .

Therefore, weight of one molecule

$\begin{aligned} = \frac{Molecular weight of C_{60} H_{122}}{Avogadro’s number} \\ = \frac{842}{6.023 \times 10^{23}} = 1.36 \times 10^{- 21} g ≃ 1.4 \times 10^{- 21} g \end{aligned}$

Some Basic Concepts of Chemistry - Result Question 24

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Some Basic Concepts of Chemistry - Result Question 24

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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