SATHEE: Some Basic Concepts of Chemistry

Some Basic Concepts of Chemistry - Result Question 2

####3. In which case is number of molecules of water maximum?

[2018]

(a) $18 m L$ of water

(b) $0.18 g$ of water

(d) $0.00224 L$ of water vapours at $1 a t m$ and $273 K$

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Solution:

$∴ 30$ moles of $H_{2}$ are required.

(1) Mass of water $= 18 \times 1 = 18 g$

Molecules of water $=$ mole $\times N_{A}$

$= \frac{18}{18} N_{A} = N_{A}$

(2) Molecules of water $=$ mole $\times N_{A}$

$= \frac{0.18}{18} N_{A} = 10^{- 2} N_{A}$

${\begin{cases} 2 \\ 管 \end{cases} .$

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Some Basic Concepts of Chemistry - Result Question 2

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