Some Basic Concepts of Chemistry - Result Question 16
####16. The number of moles of $KMnO_4$ reduced by one mole of $KI$ in alkaline medium is:
[2005]
(a) one
(b) two
(c) five
(d) one fifth
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Solution:
- (b) In weak alkaline medium, the equation is:
$2 MnSO_4^{-}+H_2 O+I^{-} \longrightarrow 2 MnO_2+IO_4^{-}+2 OH^{-}$
Hence, one mole of $KI$ reduce, 2 moles of $KMnO_4$.
