SATHEE: Some Basic Concepts of Chemistry

Some Basic Concepts of Chemistry - Result Question 13

####13. Volume occupied by one molecule of water (density $= 1 g c m^{- 3}$ ) is :

[2008]

(a) $9.0 \times 10^{- 23} c m^{3}$

(b) $6.023 \times 10^{- 23} c m^{3}$

(c) $3.0 \times 10^{- 23} c m^{3}$

(d) $5.5 \times 10^{- 23} c m^{3}$

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Solution:

(c) $∴$ Volume occupied by 1 gram water $= 1 c m^{3}$ or Volume occupied by

$\frac{6.023 \times 10^{23}}{18}$ molecules of water $= 1 c m^{3}$

$[∴ 1 g water = \frac{1}{18} moles of water]$

Thus, volume occupied by 1 molecule of water $= \frac{1 \times 18}{6.023 \times 10^{23}} c m^{3} = 3.0 \times 10^{- 23} c m^{3}$ .

i.e. the correct answer is option (c).

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Some Basic Concepts of Chemistry - Result Question 13

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