Redox Reactions - Result Question 4

####4. What is the change in oxidation number of carbon in the following reaction?

$CH_4(g)+4 Cl_2(g) \longrightarrow CCl_4(l)+4 HCl(g)$

(a) 0 to +4

(b) -4 to +4

(c) 0 to -4

(d) +4 to +4

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Solution:

(b) $\stackrel{-4}{C} H_4(g)+4 Cl_2(g) \to \stackrel{+4}{C C l_4}(l)+4 HCl(g)$

Change in oxidation state of carbon is -4 to +4 .



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