Redox Reactions - Result Question 4
####4. What is the change in oxidation number of carbon in the following reaction?
$CH_4(g)+4 Cl_2(g) \longrightarrow CCl_4(l)+4 HCl(g)$
(a) 0 to +4
(b) -4 to +4
(c) 0 to -4
(d) +4 to +4
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Solution:
(b) $\stackrel{-4}{C} H_4(g)+4 Cl_2(g) \to \stackrel{+4}{C C l_4}(l)+4 HCl(g)$
Change in oxidation state of carbon is -4 to +4 .