Redox Reactions - Result Question 15
####16. When $Cl_2$ gas reacts with hot and concentrated sodium hydroxide solution, the oxidation number of chlorine changes from :
[2012]
(a) zero to +1 and zero to -5
(b) zero to -1 and zero to +5
(c) zero to -1 and zero to +3
(d) zero to +1 and zero to -3
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Solution:
- (b) On reaction with hot and concentrated alkali a mixture of chloride and chlorate is formed
$3 Cl_2+3 NaOH$ (excess) $\xrightarrow{\text{ Hot }}$
$ \begin{equation*} 5 NaCl+NaClO_3+3 H_2 O \tag{1} \end{equation*} $
