Redox Reactions - Result Question 10
####10. The oxidation number of chromium in potassium dichromate is
(a) +6
(b) -5
(c) -2
(d) +2
[1988, 1995]
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Solution:
- (a) Let $x=$ oxidation no. of $Cr$ in $K_2 Cr_2 O_7$. $\therefore(2 \times 1)+(2 \times x)+7(-2)=0$ or $2+2 x-14=0$ or $x=+6$.