SATHEE: Redox Reactions - Result Question 1

Redox Reactions - Result Question 1

####1. $Z n$ gives $H_{2}$ gas with $H_{2} S O_{4}$ and $H C l$ but not with $H N O_{3}$ because

[2002]

(a) $Z n$ acts as an oxidising agent when it reacts with $H N O_{3}$

(b) $H N O_{3}$ is weaker acid than $H_{2} S O_{4}$ and $H C l$

(d) $N O_{3}^{-}$ is reduced in preference to hydronium ion

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Solution:

(d) Zinc gives $H_{2}$ gas with dil $H_{2} S O_{4} / H C l$ but not with $H N O_{3}$ because in $H N O_{3}, N O_{3}^{-}$ ion is reduced and give $N H_{4} N O_{3}, N_{2} O, N O$ and $N O_{2}$

$\begin{bmatrix} ended with \end{matrix}$

$Z n$ is above of hydrogen in electrochemical series. So, $Z n$ displaces $H_{2}$ from dilute $H_{2} S O_{4}$ and $H C l$ with liberation of $H_{2}$ .

$Z n + H_{2} S O_{4} \to Z n S O_{4} + H_{2}$

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Redox Reactions - Result Question 1

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