SATHEE: Organic Chemistry Some Basic Principles and Techniques

Organic Chemistry Some Basic Principles and Techniques - Result Question 45

####51. In Duma’s method for estimation of nitrogen, $0.25 g$ of an organic compound gave $40 m L$ of nitrogen collected at $300 K$ temperature and 725 $m m$ pressure. If the aqueous tension at $300 K$ is $25 m m$ , the percentage of nitrogen in the compound is :

[2015]

(a) 18.20

(b) 16.76

(d) 17.36

Show Answer

Solution:

(b) Wt. of organic substance $= 0.25 g$

$V_{1} = 40 m L, T_{1} = 300 K$

$P_{1} = 725 - 25 = 700 m m$ of $H g$

$P_{2} = 760 m m$ of $H g$ (at STP)

$T_{2} = 273 K$

$\frac{P_{1} V_{1}}{T_{1}} = \frac{P_{2} V_{2}}{T_{2}}$

$V_{2}$ (Volume of nitrogen at STP)

$= \frac{273 \times 700 \times 40}{300 \times 760} = 33.52 m L$

Percentage of nitrogen

$\begin{aligned} = \frac{28 \times volume of N_{2} at STP \times 100}{22400 \times wt. of organic substance} \\ = \frac{28 \times 33.52 \times 100}{22400 \times 0.25} = 16.76 \end{aligned}$

Organic Chemistry Some Basic Principles and Techniques - Result Question 45

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Organic Chemistry Some Basic Principles and Techniques - Result Question 45

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Menu