SATHEE: Organic Chemistry Some Basic Principles and Techniques

Organic Chemistry Some Basic Principles and Techniques - Result Question 20

####22. When the hybridization state of carbon atom changes from $s p^{3}$ to $s p^{2}$ and finally to $s p$ , the angle between the hybridized orbitals

[1993]

(a) decreases gradually

(b) decreases considerably

(d) increases progressively.

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Solution:

(d) Angle increases progressively $s p^{3} (109^{\circ} 28^{'}), s p^{2} (120^{\circ}), s p (180^{\circ})$

23 .CC(C=O)=CC(C)O

4-Hydroxy-2-methylpent-2-en-1-al

(b) $^{1} C H_{3} -^{2} C =^{3} C H -^{4} C H_{3}$ 2-Methyl-2-butene

(d) $\overset{s p^{3}}{C} H_{3} - \overset{s p^{2}}{C} H = \overset{s p^{2}}{C} H - \overset{s p^{3}}{C} H_{2} - \overset{s p^{2}}{C} H = \overset{s p^{2}}{C} H - C \equiv \overset{s p}{C} H$

Organic Chemistry Some Basic Principles and Techniques - Result Question 20

Solution:

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Organic Chemistry Some Basic Principles and Techniques - Result Question 20

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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