Organic Chemistry Some Basic Principles and Techniques - Result Question 15
####16. The structural formula of a compound is $CH_3-CH=C=CH_2$. The types of hybridization at the four carbons from left to right are
(a) $s p^{2}, s p^{2}, s p^{2}, s p^{3}$
(c) $s p^{3}, s p^{2}, s p, s p^{2}$
(b) $s p^{2}, s p^{3}, s p^{2}, s p^{2}$
(d) $s p^{3}, s p^{2}, s p^{2}, s p^{2}$
[1996]
is
(a) 1,3-isopropyl-3-methylpropane
(b) 2,3,6-trimethylheptane
(c) 2,5,6-trimethylheptane
(d) 2,6,3-trimethylheptane
Show Answer
Solution:
(c) $CH_3-CH=C=CH_2$
