SATHEE: Nuclear Chemistry - Result Question 8

Nuclear Chemistry - Result Question 8

####11. $_{9} 2^{235} U +_{0}^{1} n \to_{9} 2^{236} U \to$ fission products + neutrons $+ 3.20 \times 10^{- 11} J$ The energy released when $1 g$ of $_{9} 2^{235} U$ finally undergoes fission is

[1997]

(a) $12.75 \times 10^{8} k J$

(b) $16.40 \times 10^{7} k J$

(d) $6.50 \times 10^{6} k J$

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Solution:

$= 3.2 \times 10^{- 11} J$

$6.023 \times 10^{23}$ atom ( 1 mole) on fission gives energy $= 3.2 \times 10^{- 11} \times 6.023 \times 10^{23} J$

$1 g$ of $_{9} 2^{235} U$ on fission gives energy

$= \frac{6.023}{235} \times 3.2 \times 10^{12} J = 8.2 \times 10^{7} k J$

Nuclear Chemistry - Result Question 8

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Nuclear Chemistry - Result Question 8

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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