Nuclear Chemistry - Result Question 6
####9. Number of neutrons in a parent nucleus $X$, which gives $ _7^{14} N$ nucleus, after two successive $\beta$ emissions, would be
[1998]
(a) 9
(b) 6
(c) 7
(d) 8
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Solution:
- (a) $ _5 X^{14} \xrightarrow{-\beta} _6 Y^{14} \xrightarrow{-\beta} _7 N^{14}$
No. of neutrons $=$ Mass number - No. of proton $=14-5=9$
