SATHEE: Nuclear Chemistry - Result Question 3

Nuclear Chemistry - Result Question 3

####4. The radioactive isotope, tritium, $(_{1}^{3} H)$ has a halflife of 12.3 years. If the initial amount of tritium is $32 m g$ , how many milligrams of it would remain after 49.2 years?

[2003]

(a) $8 m g$

(b) $1 m g$

(d) $4 m g$

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Solution:

Initial amount $(N_{0}) = 32 m g$

Total time $= 49.2$ years

No. of half lives $(n) = \frac{T}{t_{1 / 2}} = \frac{49.2}{12.3} = 4$

Now $N_{t} = N_{0} (\frac{1}{2})^{n} = 32 (\frac{1}{2})^{4} = \frac{32}{16} = 2 m g$

Hence $32 m g$ becomes $2 m g$ in 49.2 years

(a) $_{92} U^{235} +_{0} n^{1} \to_{54} X e^{139} +_{38} S r^{94} + X$

$92 + 0 = 54 + 38 + a \Rightarrow a = 0$

$235 + 1 = 139 + 94 + b \Rightarrow b = 3$ So, $X = 3_{0} n^{1}$

i.e 3 neutrons.

Nuclear Chemistry - Result Question 3

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Nuclear Chemistry - Result Question 3

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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