SATHEE: Nuclear Chemistry - Result Question 2

Nuclear Chemistry - Result Question 2

####2. A nuclide of an alkaline earth metal undergoe radioactive decay by emission of the $α$ -particle: in succession. The group of the periodic tabl, to which the resulting daughter element wouk belong is

$[2005$

(a) Gr. 4

(b) Gr. 6

(d) Gr. 16

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Solution:

(c) When IIA group element (Ra) emits one $α$ -particle its group no. decreases by two unit. i.e., go into zero group (Gr. 16) But as it is radioactive thus due to successive emission last product is $P b$ i.e., (Gr.14).

Balancing the mass and atomic numbers on both sides $_{2} 8^{60} X +_{0}^{1} n \to_{2} 7^{60} C o +_{1}^{1} H$

Thus $X$ should be $_{2} 8^{60} N i$

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Nuclear Chemistry - Result Question 2

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