Nuclear Chemistry - Result Question 2
####2. A nuclide of an alkaline earth metal undergoe radioactive decay by emission of the $\alpha$-particle: in succession. The group of the periodic tabl, to which the resulting daughter element wouk belong is
$[2005$
(a) Gr. 4
(b) Gr. 6
(c) Gr. 14
(d) Gr. 16
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Solution:
- (c) When IIA group element (Ra) emits one $\alpha$-particle its group no. decreases by two unit. i.e., go into zero group (Gr. 16) But as it is radioactive thus due to successive emission last product is $Pb$ i.e., (Gr.14).
(c) $[X]+ _0^{1} n \to _27^{60} Co+ _1^{1} H$
Balancing the mass and atomic numbers on both sides $ _28^{60} X+ _0^{1} n \to _27^{60} Co+ _1^{1} H$
Thus $X$ should be $ _28^{60} Ni$
