SATHEE: Hydrogen - Result Question 10

Hydrogen - Result Question 10

####13. (i) $H_{2} O_{2} + O_{3} \to H_{2} O + 2 O_{2}$

(ii) $H_{2} O_{2} + A g_{2} O \to 2 A g + H_{2} O + O_{2}$

Role of hydrogen peroxide in the above reactions is respectively -

[2014]

(a) Oxidizing in (i) and reducing in (ii)

(b) Reducing in (i) and oxidizing in (ii)

(d) Oxidizing in (i) and (ii)

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Solution:

(ii)

Hence, in both the reactions, $H_{2} O_{2}$ is acting as an reducing agent.

Half equations for oxidation of $H_{2} O_{2}$ .

(i) In acidic medium

$H_{2} O_{2} ⟶ 2 H^{+} + O_{2} + 2 e^{-}$

(ii) In basic medium

$H_{2} O_{2} + O H^{-} ⟶ 2 H_{2} O + O_{2} + 2 e^{-}$

Half equations for reduction of $H_{2} O_{2}$ :

(i) In acidic medium

$H_{2} O_{2} + 2 H^{+} + 2 e^{-} ⟶ 2 H_{2} O$

(ii) In basic medium

$H_{2} O_{2} + 2 e^{-} ⟶ 2 O H^{-}$

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Hydrogen - Result Question 10

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