Hydrogen - Result Question 10
####13. (i) $H_2 O_2+O_3 \to H_2 O+2 O_2$
(ii) $H_2 O_2+Ag_2 O \to 2 Ag+H_2 O+O_2$
Role of hydrogen peroxide in the above reactions is respectively -
[2014]
(a) Oxidizing in (i) and reducing in (ii)
(b) Reducing in (i) and oxidizing in (ii)
(c) Reducing in (i) and (ii)
(d) Oxidizing in (i) and (ii)
Show Answer
Solution:
(c) (i)
(ii)
Hence, in both the reactions, $H_2 O_2$ is acting as an reducing agent.
Half equations for oxidation of $H_2 O_2$.
(i) In acidic medium
$ H_2 O_2 \longrightarrow 2 H^{+}+O_2+2 e^{-} $
(ii) In basic medium
$H_2 O_2+OH^{-} \longrightarrow 2 H_2 O+O_2+2 e^{-}$
Half equations for reduction of $H_2 O_2$ :
(i) In acidic medium
$H_2 O_2+2 H^{+}+2 e^{-} \longrightarrow 2 H_2 O$
(ii) In basic medium
$H_2 O_2+2 e^{-} \longrightarrow 2 OH^{-}$
