SATHEE: Hydrocarbons - Result Question 71

Hydrocarbons - Result Question 71

####73. In the following reaction, $C_{6} H_{5} C H_{2} B r$ $\to_{2 . H_{3} O^{+}}^{1 . M g, Ether} X$ , the product ’ $X$ ’ is

[2010]

(a) $C_{6} H_{5} C H_{2} C H_{2} C_{6} H_{5}$

(b) $C_{6} H_{5} C H_{2} O C H_{2} C_{6} H_{5}$

(c) $C_{6} H_{5} C H_{2} O H$

(d) $C_{6} H_{5} C H_{3}$

Show Answer

Solution:

(d) $C_{6} H_{5} C H_{2} B r + M g \overset{ether}{\to}$

$C_{6} H_{5} C H_{2} M g B r \overset{H_{2} O / H^{+}}{\to} C_{6} H_{5} C H_{3} + M g B r (O H)$

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