Hydrocarbons - Result Question 71

####73. In the following reaction, $C_6 H_5 CH_2 Br$ $\xrightarrow[2 . H_3 O^{+}]{1 . Mg \text{, Ether }} X$, the product ’ $X$ ’ is

[2010]

(a) $C_6 H_5 CH_2 CH_2 C_6 H_5$

(b) $C_6 H_5 CH_2 OCH_2 C_6 H_5$

(c) $C_6 H_5 CH_2 OH$

(d) $C_6 H_5 CH_3$

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Solution:

(d) $C_6 H_5 CH_2 Br+Mg \xrightarrow{\text{ ether }}$

$C_6 H_5 CH_2 MgBr \xrightarrow{H_2 O / H^{+}} C_6 H_5 CH_3+Mg Br(OH)$



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