Hydrocarbons - Result Question 60
####62. $R-CH_2-CCl_2-R \xrightarrow{\text{ Reagent }} R-C \equiv C-R$ The reagent is
[1993]
(a) $Na$
(b) $HCl$ in $H_2 O$
(c) $KOH$ in $C_2 H_5 OH$
(d) $Zn$ in alcohol.
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Solution:
- (c) On heating ethylene chloride (1, 1 dichloro ethane) with alcoholic $KOH$ followed by sodamide, alkyne is obtained
$ \begin{aligned} & R-CH_2-CCl_2-R \\ & \xrightarrow{\text{ alc. } KOH} R-CH=CCl-R \\ & \xrightarrow{NaNH_2} R-C \equiv C-R \end{aligned} $
