Hydrocarbons - Result Question 50
####52. In the reaction
$H-C \equiv CH \frac{(1) NaNH_2 / \text{ liq. } NH_3}{(2) CH_3 CH_2 Br} X$
$ \frac{\text{ (1) } NaNH_2 / \text{ liq. } NH_3}{\text{ (2) } CH_3 CH_2 Br} Y $
$X$ and $Y$ are
[2016]
(a) $X=1$-Butyne; $Y=3$-Hexyne
(b) $X=2$-Butyne; $Y=3$-Hexyne
(c) $X=2$-Butyne; $Y=2$-Hexyne
(d) $X=1$-Butyne; $Y=2$-Hexyne
Show Answer
Solution:
- (a)
$
HC \equiv CH \xrightarrow[\text{ liq. } NH_3]{NaNH_2} HC \equiv \overline{C} \stackrel{\oplus}{Na}
$
