SATHEE: Hydrocarbons - Result Question 49

Hydrocarbons - Result Question 49

####51. Predict the correct intermediate and product in the following reaction :

[2017]

$H_{3} C - C \equiv C H \to_{H g S O_{4}}^{H_{2} O, H_{2} S O_{4}} \underset{(A)}{Intermediate} \to \underset{(B)}{product}$

(a) $A : H_{3} C - \underset{∣}{C} = C H, B : H_{3} C - \underset{∣}{C} = C H_{2}$

(b) $A : H_{3} C - \underset{|}{C} = C H_{3}, B : H_{3} C - C \equiv C H$

(d) $A : H_{3} C - \underset{S O_{4}}{C} = C H_{2}, B : H_{3} C - C - C H_{3}$

Show Answer

Solution:

(B)

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Hydrocarbons - Result Question 49

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