SATHEE: Hydrocarbons - Result Question 37

Hydrocarbons - Result Question 37

####39. In reaction sequence

[1997]

$C H_{2} = C H_{2} \to_{acid}^{Hypochlorous} M \overset{R}{\to} \underset{C H_{2} O H}{C H_{2} O H}$

molecule ’ $M$ ’ and reagent ’ $R$ ’ respectively are

(a) $C H_{3} C H_{2} C l$ and $N a O H$

(b) $C H_{3} C H_{2} O H$ and $H_{2} S O_{4}$

(c) $C H_{2} C l - C H_{2} O H$ and aqueous $N a H C O_{3}$

(d) $C H_{2} - C H_{2}$ and heatCOC

Show Answer

Solution:

(c) We know that

$M = C H_{2} O H - C H_{2} C l$ and $R = N a H C O_{3}$

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Hydrocarbons - Result Question 37

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