####31. The compound $CH_3-\stackrel{+}{C}=CH-CH_3$ on reaction with $NaIO_4$ in the presence of $KMnO_4$ gives
[2003]
(a) $CH_3 CHO+CO_2$
(b) $CH_3 COCH_3$
(c) $CH_3 COCH_3+CH_3 COOH$
(d) $CH_3 COCH_3+CH_3 CHO$
(c)
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