Equilibrium - Result Question 99
####103. In which of the following solvents, $AgBr$ will have the highest solubility?
[1992]
(a) $10^{-3} M NaBr$
(b) $10^{-3} M NH_4 OH$
(c) Pure water
(d) $10^{-3} M HBr$
Show Answer
Solution:
- (b) $AgBr$ has the highest solubility in $10^{-3} M$
$NH_4 OH . AgBr$ is less soluble in $NaBr$ and $HBr$ due to presence of common ion $(Br)$. With $NH_4 OH, AgBr$ will react as:
$AgBr(s)+2 NH_4 OH$ (aq.)
$arrow[Ag(NH_3)_2] Br($ aq. $)+2 H_2 O(l)$
Hence, the highest solubility with $NH_4 OH$ solution.
