SATHEE: Equilibrium - Result Question 94

Equilibrium - Result Question 94

####98. The solubility products of $C u S, A g_{2} S$ and $H g S$ are $10^{- 31}, 10^{- 44}, 10^{- 54}$ respectively. The solubilities of these sulphides are in the order

[1997]

(a) $A g_{2} S > H g S > C u S$

(b) $A g_{2} S > C u S > H g S$

(d) $C u S > A g_{2} S > H g S$

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Solution:

(b) For Binary salts like $Misplaced &$ , solubilty,

$s = \sqrt{K_{s p}}$

$\Rightarrow s_{C u S} = \sqrt{10^{- 31}} = 3.16 \times 10^{- 16}$ ,

$s_{H g S} = \sqrt{10^{- 54}} = 10^{- 27}$

For $A g_{2} S \to \underset{2 s}{2 A g^{+}} + \underset{s}{S^{2}}$

$K_{s p} = 4 s^{3}$ or $s_{A g_{2} S} = \sqrt[3]{\frac{K_{s p}}{4}} = \sqrt[3]{\frac{10^{- 44}}{4}}$

$= \sqrt[3]{0.25 \times 10 \times 10^{- 45}} = 13.54 \times 10^{- 16}$

$∴$ The order is $A g_{2} S > C u S > H g S$

Equilibrium - Result Question 94

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Equilibrium - Result Question 94

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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