Equilibrium - Result Question 92

####96. Solubility of a $M_2 S$ salt is $3.5 \times 10^{-6}$, then its solubility product will be

[2001]

(a) $1.7 \times 10^{-16}$

(b) $1.7 \times 10^{-6}$

(c) $1.7 \times 10^{-18}$

(d) $1.7 \times 10^{-12}$

Show Answer

Solution:

(a) $M_2 S \rightarrow \underset{2 s}{2 M^{+}}+\underset{s}{S^{–}}$

Solubility product $=(2 s)^{2}(s)=4 s^{3}$

$=4(3.5 \times 10^{-6})^{3}=1.7 \times 10^{-16}$



NCERT Chapter Video Solution

Dual Pane