SATHEE: Equilibrium - Result Question 86

Equilibrium - Result Question 86

####90. $H_{2} S$ gas when passed through a solution of cations containing $H C l$ , precipitates the cations of second group of qualitative analysis but not those belonging to the fourth group. It is because

[2005]

(a) presence of $H C l$ decreases the sulphide ion concentration.

(b) solubility product of group II sulphides is more than that of group IV sulphides.

(d) sulphides of group IV cations are unstable in $H C l$ .

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Solution:

(a) $I V^{th}$ group needs higher $S^{2 -}$ ion concentration.

In presence of $H C l$ , the dissociation of $H_{2} S$ decreases hence produces less amount of sulphide ions due to common ion effect, thus $H C l$ decreases the solubility of $H_{2} S$ which is sufficient to precipitate $I I^{nd}$ group radicals.

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Equilibrium - Result Question 86

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